While (!String.valueOf(censor).equals(wordToGuess))īoolean correct = false //lets the user know if the letter is in the word or notīoolean repeated = false //check if user guessed the same letter twice
("Your secret word is: ") // prints an array of chars with the same length as stringįor (int index = 0 index < length index++) String wordToGuess = input.nextLine().toUpperCase() Ĭhar wordToGuessChars = wordToGuess.toCharArray() //creates character array of stringsĬhar censor = wordToGuess.toCharArray() On guessing the word successfully, the program will show the number of attempts at the end.If the user already guessed the letter before, the program will tell the user of that and show their previous guesses without repeating any letters.It will also show the progress of the censored word after each guess.The program will tell the guesser if their guessed letter is in the word or not.The word will be censored by the program.The game will first ask the user to type a word that the 2nd person/guesser will then guess.Also, while guessing the word, if a guessed letter is not in the word, it is written separately on the side, so that the guesser does not waste a chance on the same word again.And for every wrong guess, the lives reduce and the guesser can run out of lives, hence losing the game.Once the guesser is coming close to guessing the word, he can attempt to guess the whole word and if he guesses it right, he/she has won the game.However,if the guessed letter does not occur in the word, the guesser loses a life and has lesser chances to guess the word currently.Once the guesser says an alphabet, if the word contains that letter and is guessed right, the other player will write it in all the correct positions of the word to be guessed.The second player/guesser now has to guess the word and has limited chances or lives to do so.The word is then displayed as XXXX with the number of Xs equal to the length of the guessed word.The first player thinks of a word which ideally should be a noun like a name of a place,animal,thing etc, but should make sure it is not a Name of a person, or any slang or informal words.Hence, the following rules explain how Hangman is played: Overview of Hangman game in Java:įirstly, we should know what kind of game Hangman is and how do we play it.
#Java code how to#
So let’s start learning how to create a hangman game in Java. Public static PieceType fromString(String value) else if (pieceType = PieceType.In this Java Program, we implement the popular game Hangman in Java. Is there a better option? Due to this, I get a lot of NullPointerExceptions while debugging? Is this a design flaw or is this something I have to deal with? Is there any way to improve on these?Ģ) I have learned a convention of assigning a null value to all objects if they are empty/not present (If a square does not contain a piece, then null is assigned). Is there any way I can clean it up ( divide it up maybe)? Something that bugs me is the implementation of isValidCastling() function and move() function. I have got some specific questions about the implementation that I would love to have answeredġ) The BoardManager.java class seems to be pretty large. The GUI is not included here but if you would like to look at it then here is my repository.
#Java code code#
I thought it would be hard to review my code without the basic classes. I hope I have not included a lot of code here. Idioms, conventions, anything that comes to your mind.
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How the same implementation can be better written.
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